El resultado son todas las combinaciones posibles para 32 dígitos de en Hexadecimal, aún no he probado sacar el volcado a un fichero para ver lo que ocupa.
for a in {a..f}{0..9} {0..9}{a..f}; do # 4bit
for b in {a..f}{0..9} {0..9}{a..f}; do # 8bit
for c in {a..f}{0..9} {0..9}{a..f}; do # 12bit
for d in {a..f}{0..9} {0..9}{a..f}; do # 16bit
for e in {a..f}{0..9} {0..9}{a..f}; do # 20bit
for f in {a..f}{0..9} {0..9}{a..f}; do # 24bit
for g in {a..f}{0..9} {0..9}{a..f}; do # 28bit
for h in {a..f}{0..9} {0..9}{a..f}; do # 32bit
for i in {a..f}{0..9} {0..9}{a..f}; do
for j in {a..f}{0..9} {0..9}{a..f}; do
for k in {a..f}{0..9} {0..9}{a..f}; do
for l in {a..f}{0..9} {0..9}{a..f}; do
for m in {a..f}{0..9} {0..9}{a..f}; do
for n in {a..f}{0..9} {0..9}{a..f}; do
for o in {a..f}{0..9} {0..9}{a..f}; do
for p in {a..f}{0..9} {0..9}{a..f}; do # 64bit
for q in {a..f}{0..9} {0..9}{a..f}; do
for r in {a..f}{0..9} {0..9}{a..f}; do
for s in {a..f}{0..9} {0..9}{a..f}; do
for t in {a..f}{0..9} {0..9}{a..f}; do
for u in {a..f}{0..9} {0..9}{a..f}; do
for v in {a..f}{0..9} {0..9}{a..f}; do
for w in {a..f}{0..9} {0..9}{a..f}; do
for x in {a..f}{0..9} {0..9}{a..f}; do
for y in {a..f}{0..9} {0..9}{a..f}; do
for z in {a..f}{0..9} {0..9}{a..f}; do
for aa in {a..f}{0..9} {0..9}{a..f}; do
for ab in {a..f}{0..9} {0..9}{a..f}; do
for ac in {a..f}{0..9} {0..9}{a..f}; do
for ad in {a..f}{0..9} {0..9}{a..f}; do
for ae in {a..f}{0..9} {0..9}{a..f}; do
for af in {a..f}{0..9} {0..9}{a..f}; do # 128bit
echo $a$b$c$d$e$f$g$h$i$j$k$l$m$n$o$p$q$r$s$t$u$v$w$x$y$z$aa$ab$ac$ad$ae$af;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
done;
Cuidado con lo que utilizáis este diccionario, porque podría utilizarse para descifrar redes Wifi con encriptación WPA.
Lo "normal" es que estas redes tengan únicamente 64bit de encriptación.
